Timeline for Select elements in a list of tuples of quaternions that satisfy a condition
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 5, 2018 at 4:29 | history | edited | J. M.'s missing motivation | CC BY-SA 4.0 | added 14 characters in body |
| Oct 4, 2018 at 6:09 | vote | accept | B.manca | ||
| Oct 3, 2018 at 15:10 | comment | added | B.manca | I tried also the solution you wrote me but it still gives me an empty list. probably there is something wrong in the definition of the list. Thank you so much! | |
| Oct 3, 2018 at 13:13 | answer | added | J. M.'s missing motivation | timeline score: 1 | |
| Oct 3, 2018 at 10:50 | review | First posts | |||
| Oct 3, 2018 at 13:04 | |||||
| Oct 3, 2018 at 10:48 | comment | added | Henrik Schumacher | You might want to use Select[ListQuad, (x ** y ** z ** w == Quaternion[1, 0, 0, 0]) &] instead. In general, you have to decide whether to use Select (function based selection) or Cases (pattern based selection). | |
| Oct 3, 2018 at 10:46 | history | asked | B.manca | CC BY-SA 4.0 |