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when toggle format what by license comment
Sep 10, 2019 at 12:11 comment added Wiliam Thank you that is indeed sorted it :)
Sep 10, 2019 at 12:07 comment added Lukas Lang If I understand you correctly, x^-Length@l[[i]] should work, no? Also, a more concise alternative: AssociationMap[ Total[x^-Length@# x^Map[Length, Select[l, ContainsAll@#]]] &, l]
Sep 10, 2019 at 11:59 history edited Αλέξανδρος Ζεγγ CC BY-SA 4.0
added 8 characters in body
Sep 10, 2019 at 11:55 history asked Wiliam CC BY-SA 4.0