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  • $\begingroup$ Wow, that's brilliant. Thank you very much! $\endgroup$ Commented Sep 24, 2019 at 8:49
  • $\begingroup$ @charl1e you're welcome! $\endgroup$ Commented Sep 24, 2019 at 8:51
  • $\begingroup$ Why is the equation modified in this way? $\endgroup$ Commented Sep 24, 2019 at 9:15
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    $\begingroup$ @xzczd We have r'[t]==Sqrt[...], then r'[t]^2==(...), and therefore ` r'[t]r''[t]==D[(...),r]r'[t]`. $\endgroup$ Commented Sep 24, 2019 at 9:21
  • $\begingroup$ I see. The ODE is deduced based on energy conservation, right? $\endgroup$ Commented Sep 24, 2019 at 9:26