Timeline for Assigning values to multiple variables from a list
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 30, 2020 at 9:52 | vote | accept | Cameron | ||
| S Jan 29, 2020 at 5:16 | history | edited | m_goldberg | CC BY-SA 4.0 | Improved formatting |
| S Jan 29, 2020 at 5:16 | history | suggested | AsukaMinato | CC BY-SA 4.0 | refine the formula |
| Jan 29, 2020 at 3:02 | review | Suggested edits | |||
| S Jan 29, 2020 at 5:16 | |||||
| Jan 29, 2020 at 2:49 | answer | added | Alx | timeline score: 2 | |
| Jan 28, 2020 at 17:54 | history | edited | Cameron | CC BY-SA 4.0 | added 66 characters in body |
| Jan 28, 2020 at 15:53 | answer | added | bcegkmqs23 | timeline score: 0 | |
| Jan 28, 2020 at 15:47 | comment | added | Cameron | and lets assume $x_3=0.0009$ | |
| Jan 28, 2020 at 15:41 | comment | added | Cameron | @bcegkmqs23 yes there is. Full solution for n = 3 looks like this: $F(x)=c+x_3-x_3*log(x_3+sqrt(x_3))$ | |
| Jan 28, 2020 at 15:27 | comment | added | Alan | For n=3, lease post the actual expression for the "solution" and an example x along with the desired answer. | |
| Jan 28, 2020 at 15:27 | comment | added | bcegkmqs23 | Is there anything after $log$ as a parameter? | |
| Jan 28, 2020 at 15:25 | review | First posts | |||
| Jan 28, 2020 at 15:28 | |||||
| Jan 28, 2020 at 15:23 | history | asked | Cameron | CC BY-SA 4.0 |