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  • $\begingroup$ Is there a way to do it where T1 is still defined? Because I need it (and T2, T3, ...) in other places. Didn't know about "Format", thanks! I could imagine using a Module or Block, but it seems so ugly... $\endgroup$ Commented Apr 19, 2020 at 13:32
  • $\begingroup$ Define the replacement rule t1r = T1 -> π Ai/(2 Ja); Then whenever you want to replace T1 use expression /. t1r $\endgroup$ Commented Apr 19, 2020 at 14:05
  • $\begingroup$ Perhaps I'm misunderstanding, but if I only have the replacement rule then there would be no way for the system to know there is a relationship between T1 and Ja and so I'd either have answers without T1 (if I used the replacement rules) or I'd have answers with a mix of T1 and Ai/Ja, but without the simplifications that can result by knowing how they inter-relate. $\endgroup$ Commented Apr 19, 2020 at 14:24
  • $\begingroup$ If you Set the value of T1, i.e. T1 = ... then T1 can never appear since it will always be replaced by its definition. A rule enables you to either not use the rule and let T1 appear or use the rule and thereby substitute for T1. Alternatively, you can define the equation T1 == ... and use the equation in a system of equations (Solve, Eliminate, Reduce, FindInstance, ...) or as an assumption in Simplify or similar. $\endgroup$ Commented Apr 19, 2020 at 14:37
  • $\begingroup$ Ok, that makes sense, thank you! If I want to do the system of equations route, do I need to do something like eq1 = T1 == ..., eq2 = T2 == ..., or is there some way to reference the T1 == and T2 == without assigning the equality to another symbol? $\endgroup$ Commented Apr 19, 2020 at 19:32