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Jul 3, 2020 at 18:13 history became hot network question
Jul 3, 2020 at 16:24 history edited MarcoB CC BY-SA 4.0
Formatted code, special characters
Jul 3, 2020 at 15:00 history tweeted twitter.com/StackMma/status/1279067390219780097
Jul 3, 2020 at 13:56 answer added Michael E2 timeline score: 4
Jul 3, 2020 at 11:23 comment added Natas From the documentation of Sqrt: Sqrt[z^2] is not automatically converted to z. (And then they recommend the usage of PowerExpand for positive, real z.)
Jul 3, 2020 at 10:34 vote accept Joe Bentley
Jul 3, 2020 at 10:27 answer added Nasser timeline score: 5
Jul 3, 2020 at 10:24 comment added Joe Bentley @chyanog why do I need refine as well as simplify?
Jul 3, 2020 at 10:20 comment added chyanog Assuming[{γ>0,s0>0},(Sqrt[s0 γ^3]+2 Sqrt[s0 γ^7]+Sqrt[s0^5 γ^7]+Sqrt[s0 γ^11]+2 s0 (Sqrt[s0 γ^5]+Sqrt[s0 γ^9]))/(γ (1+s0 γ+γ^2)^2)//Refine//Simplify]
Jul 3, 2020 at 10:05 history asked Joe Bentley CC BY-SA 4.0