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May 3, 2021 at 13:21 comment added j.foobles Let us continue this discussion in chat.
May 3, 2021 at 13:06 comment added j.foobles here is the same file with the streamplot - looks similar, but slightly different: 1drv.ms/u/s!Ak_7kWMZ0x15hJpvJB37Nljs_saQPw?e=eqRpWi
May 3, 2021 at 12:57 comment added Ulrich Neumann @j.foobles You evaluate the same streamplot as in my answer?
May 3, 2021 at 12:53 comment added j.foobles Hi @Ulrich Neumann, I am a bit confused - perhaps some of the code copied across incorrectly from Mathematica. Nevertheless I am convinced that the denominator function has some zeroes, so I've attached a .nb file here: 1drv.ms/u/s!Ak_7kWMZ0x15hJpuG74r3VEUFQIkTQ?e=dbay6L
May 3, 2021 at 12:39 comment added Ulrich Neumann @j.foobles If I plot B[0,t,5,1,1/2] in the range -2<t<2 I see a function without zeros!
May 3, 2021 at 12:33 comment added Ulrich Neumann @j.foobles You might plot your "trajectories" together with the stream plot, fits quite well!
May 3, 2021 at 11:41 comment added j.foobles Hi Ulrich, doesn't StreamPlot just plot the velocity field rather than the trajectory x(t) parametrically? Also, it's a bit hard to tell whether the field shown above has singularities, but I have included a graph showing that the denominator of V(x,t) is definitely zero at points. Ideally I'd like to solve the ODE while dealing with the singular points.
May 3, 2021 at 9:08 history edited Ulrich Neumann CC BY-SA 4.0
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May 3, 2021 at 8:42 history edited Ulrich Neumann CC BY-SA 4.0
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May 3, 2021 at 8:28 history edited Ulrich Neumann CC BY-SA 4.0
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May 3, 2021 at 8:22 history answered Ulrich Neumann CC BY-SA 4.0