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  • $\begingroup$ why not simply ClearAll[chooseFun]; chooseFun=RandomChoice? $\endgroup$ Commented May 22, 2021 at 14:06
  • $\begingroup$ @kglr Honestly, I was not aware of that function. Does chooseFun[x] evaluate properly though, in particular if one of the options is a user defined function like Log[x+1] or x^2_x as opposed to a system one like Log or Sqrt? (I ask because I usually think about f[x_]:=x^2 as saying "take x^2 and replace x by whatever is given", but chooseFun=RandomChoice doesn't take an input which confuses me.) $\endgroup$ Commented May 22, 2021 at 14:12
  • $\begingroup$ you need to use it as chooseFunb[{Sqrt, Log}]@xx or as fa =chooseFunb[{Sqrt, Log}]; fa@x $\endgroup$ Commented May 22, 2021 at 14:15
  • $\begingroup$ alternatively, you can define choseFun as ClearAll[chooseFun]; chooseFun := RandomChoice[{Sqrt, Log}]; Then chooseFun[t] gives Sqrt[t] or Log[t] at each invocation. $\endgroup$ Commented May 22, 2021 at 14:20
  • $\begingroup$ @kglr Sorry I am not understanding stuff, and/or I have not explained my question well. First, why chooseFunb in the earlier comment (i.e. why is there a "b" there?). Second, with ClearAll[chooseFun] chooseFun := RandomChoice[{Sqrt, Log}];, chooseFun[t] would (potentially) switch from Sqrt to Log on different evaluations, wouldn't it? $\endgroup$ Commented May 22, 2021 at 14:24