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May 15, 2023 at 13:36 history edited Mam Mam CC BY-SA 4.0
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May 14, 2023 at 9:31 comment added Mam Mam @Roland F, thanks for the comment! $r$ is just a coordinate, $\rho$ is a polar coordinate ($1/r = 1/\sqrt{\rho^2+z^2}$). $1/r$ is Coulomb's low
May 13, 2023 at 17:33 answer added Roland F timeline score: 2
May 13, 2023 at 14:24 comment added Roland F If $r=(\rho,z,\phi), what do you means by 1/r
May 13, 2023 at 12:33 vote accept Mam Mam
May 12, 2023 at 16:03 answer added Alex Trounev timeline score: 1
May 12, 2023 at 14:14 history edited Mam Mam
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May 12, 2023 at 14:04 history edited Mam Mam CC BY-SA 4.0
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May 12, 2023 at 13:19 history edited Mam Mam CC BY-SA 4.0
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May 11, 2023 at 21:47 comment added Mam Mam @Alex Trounev, your feedback is needed )
May 11, 2023 at 21:47 history asked Mam Mam CC BY-SA 4.0