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    $\begingroup$ Yes it is. Also we can't handle large nmax*jmax with NMinimize. $\endgroup$ Commented May 16, 2023 at 2:31
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    $\begingroup$ Use pts = Reap[ NMinimize[{Kx + Px, con}, var, StepMonitor :> Sow[var]]][[2, 1]]; and ListPlot[Table[pts[[All, i]], {i, 4}], PlotLegends -> Take[var, 4], PlotRange -> All] $\endgroup$ Commented May 17, 2023 at 3:49
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    $\begingroup$ You can try, but unfortunately, EvaluationMonitor is not working with NMinimize as expected it is why we use StepMonitor (see Options for NMinimize for details). $\endgroup$ Commented May 17, 2023 at 9:03
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    $\begingroup$ @MamMam You can use it but result is not the same as evaluated with StepMonitor. $\endgroup$ Commented May 17, 2023 at 11:36
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    $\begingroup$ @MamMam Yes it is. This is well know mathematical problem. You can ask about this problem on math.stackexchange.com $\endgroup$ Commented May 18, 2023 at 3:16