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Oct 3 at 0:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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May 11, 2024 at 7:30 comment added Daniel Huber Simply use List1 /. Thread[b -> {b1, b2, b3}]
May 10, 2024 at 18:05 history edited user64494 CC BY-SA 4.0
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May 10, 2024 at 17:17 history edited seva011 CC BY-SA 4.0
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May 10, 2024 at 17:09 history edited seva011 CC BY-SA 4.0
added 462 characters in body
May 10, 2024 at 16:33 answer added lericr timeline score: 1
May 10, 2024 at 16:26 history edited seva011 CC BY-SA 4.0
edited title
May 10, 2024 at 16:21 history edited seva011 CC BY-SA 4.0
edited title
May 10, 2024 at 16:12 history asked seva011 CC BY-SA 4.0