Timeline for Finding the Complete Silhouette Area Formula Given a Convex Polyhedron
Current License: CC BY-SA 4.0
3 events
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| Oct 18, 2024 at 17:56 | comment | added | Romogi | I meant to actually output the exact analytic formula for the area. Something like $f(P_i,r,p)=A$ , where $P_i$ is the initial polygon's coordinates, $r$ is the rotation, $p$ is the plane it is projected onto, and $A$ is the area. It is difficult to find this formula by trial an error manually and thought maybe Mathematica could help find it because it would be large and complicated. Maybe most people don't care about an exact formula, but I do. But what you did is cool. | |
| Oct 18, 2024 at 16:58 | comment | added | Romogi | I am always partial to large, complicated formula's because it explains things perfectly and plugging and chugging is a lot easier than describing things verbally. | |
| Oct 18, 2024 at 14:53 | history | answered | cvgmt | CC BY-SA 4.0 |