Skip to main content
Mathematica

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

Required fields*

6
  • $\begingroup$ Interesting improvement of my answer! Stil I don't understand, why your weights( actually commented out) only take place in the spa matrix and not in a generalized Pseudoinverese $\endgroup$ Commented Jan 22 at 9:50
  • $\begingroup$ @UlrichNeumann It's there, see PseudoInverse[(*wlst*)? :) $\endgroup$ Commented Jan 22 at 9:52
  • $\begingroup$ @UlrichNeumann Code updated, now the weight function can be easily tested by adding a fifth argument to matGFDM. $\endgroup$ Commented Jan 22 at 10:18
  • 1
    $\begingroup$ I tried weighted approach too, with weights, depending on the inverse distance 1/Sqrt[(xi-xj)^2+(yi-yj)^2] but the results are discouraging. Equal results if number of neighbors is smaller than the number of taylorterms. Worse results if the number of neighbors is greater. $\endgroup$ Commented Jan 22 at 16:54
  • $\begingroup$ @UlrichNeumann The paper sciencedirect.com/science/article/pii/0045794980901492 uses $\frac{1}{d^3}$ where $d$ is the distance, but according to my test, it doesn't seem to be great, either… Once again, I'm not sure if I've missed something. $\endgroup$ Commented Jan 23 at 8:12