Timeline for How to calculate contour integrals with Mathematica?
Current License: CC BY-SA 3.0
23 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 29 at 14:38 | answer | added | Greg Hurst | timeline score: 3 | |
| Jul 3, 2022 at 3:59 | comment | added | user64494 | See math.stackexchange.com/questions/1189503/… . | |
| Apr 23, 2020 at 15:45 | comment | added | NeAr | how about an assumption on z?? | |
| Aug 11, 2015 at 2:56 | history | edited | Michael E2 | edited tags | |
| Mar 29, 2014 at 20:48 | history | edited | Artes | edited tags | |
| Dec 3, 2013 at 7:17 | comment | added | Artes | @rm-rf Thanks for the bounty! | |
| S Dec 2, 2013 at 18:55 | history | bounty ended | rm -rf♦ | ||
| S Dec 2, 2013 at 18:55 | history | notice removed | rm -rf♦ | ||
| Dec 1, 2013 at 8:13 | vote | accept | user64494 | ||
| Nov 28, 2013 at 9:38 | comment | added | Alexei Boulbitch | As much as I recon this type of integrals were discussed in the book of Nikolos Muschelischwili "Some basic problems of the mathematical theory of elasticity". P. Noordhoff, Groningen 1953, where a general approach has been formulated, a rather easy one. | |
| Nov 27, 2013 at 18:23 | answer | added | xslittlegrass | timeline score: 14 | |
| Nov 26, 2013 at 22:07 | comment | added | Svend Tveskæg | I could be wrong, but how is this a Mathematica question? Isn't it a mathatics question? | |
| Nov 26, 2013 at 19:42 | history | tweeted | twitter.com/#!/StackMma/status/405421391438045184 | ||
| S Nov 26, 2013 at 18:12 | history | bounty started | rm -rf♦ | ||
| S Nov 26, 2013 at 18:12 | history | notice added | rm -rf♦ | Reward existing answer | |
| Nov 26, 2013 at 18:05 | history | edited | rm -rf♦ | CC BY-SA 3.0 | edited tags; edited title |
| Oct 16, 2013 at 23:15 | comment | added | Daniel Lichtblau | I just looked at Plot[Re[I*Exp[I*t]/(4 Exp[I*t]^2 + 4 Exp[I*t] + 3)^(1/2)], {t, 0, 2 Pi}] and likewise for the imaginary part. They indicate jumps at the points I had stated, and visually it is clear that negating between those points will give a continuous branch. I realize this is not a proof, but it does indicate how you can proceed to get a numerical result. The two values are +-Pi*I, by the way. | |
| Oct 16, 2013 at 18:39 | comment | added | user64494 | Could you explain it (especially between $2\pi/3$ and $4\pi/3$) in detail? | |
| Oct 16, 2013 at 16:09 | comment | added | Daniel Lichtblau | A plot of the function indicates that a continuous branch can be obtained by negating the function between 2Pi/3 and 4Pi/3. | |
| Oct 15, 2013 at 21:28 | answer | added | Artes | timeline score: 70 | |
| S Oct 15, 2013 at 16:59 | history | suggested | Hector | CC BY-SA 3.0 | LaTeX formatting |
| Oct 15, 2013 at 16:41 | review | Suggested edits | |||
| S Oct 15, 2013 at 16:59 | |||||
| Oct 15, 2013 at 16:01 | history | asked | user64494 | CC BY-SA 3.0 |