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Jun 4, 2014 at 1:34 history closed Sjoerd C. de Vries
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Jun 3, 2014 at 18:04 answer added Cassini timeline score: 4
Jun 3, 2014 at 17:37 comment added Sjoerd C. de Vries Just use your domain exactly as you specified it in the question as an argument of Boole. Don't make it more complicated than necessary.
Jun 3, 2014 at 17:08 comment added Mahdi Only for the sake of math: it you redefine variables as $X=x$, $Y=2y$ and $Z=3z$, you see that the domain is a sphere!
Jun 3, 2014 at 16:59 history edited Dr. belisarius CC BY-SA 3.0
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Jun 3, 2014 at 16:57 answer added Dr. belisarius timeline score: 4
Jun 3, 2014 at 15:53 review Close votes
Jun 4, 2014 at 1:34
Jun 3, 2014 at 15:47 comment added user14738 Can be this correct? Integrate[(Sqrt[(1 - 9 z^2) (1 - 9 z^2 - 4 y^2)]) Boole[-Sqrt[ 1 - x^2 - 4 y^2]/3 <= z <= Sqrt[1 - x^2 - 4 y^2]/3], {x, -1, 1}, {y, -1/2, 1/2}, {z, -1/3, 1/3}]
Jun 3, 2014 at 15:33 review First posts
Jun 3, 2014 at 16:13
Jun 3, 2014 at 15:32 comment added user14738 thank you...I'll inform you when i find something
Jun 3, 2014 at 15:31 comment added Sjoerd C. de Vries Please, check the documentation of Integrate. Specifically, look into the Scope section, subsection Integrals over Regions
Jun 3, 2014 at 15:29 comment added user14738 Yeah...but no one talks about triple integrals
Jun 3, 2014 at 15:28 comment added user14738 I know...but which is the syntax I've to use?
Jun 3, 2014 at 15:27 comment added Öskå Where.., there are Integrate Sqrt and all.. :)
Jun 3, 2014 at 15:26 comment added user14738 I asked how to in fact...
Jun 3, 2014 at 15:17 history asked user14738 CC BY-SA 3.0