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$\begingroup$ Look at both of them. you should find out difference of them. My answer is just answer of the principal question. $\endgroup$

Nimbigli
– Nimbigli

2014-12-01 14:41:18 +00:00
Commented Dec 1, 2014 at 14:41
1

$\begingroup$ You should read Aron's answer more carefully, he shows you how you can write a better code which is even simpler. Another simple one-liner: b = PolarPlot[Cos[2 [Theta]], {\[Theta], $MachineEpsilon, #}, PlotRange -> 1] & /@ Range[0, 2 Pi, 0.02 Pi]; $\endgroup$

C. E.
– C. E. ♦

2014-12-02 02:39:52 +00:00
Commented Dec 2, 2014 at 2:39

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