Skip to main content
Mathematica

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

Required fields*

5
  • $\begingroup$ Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Read the faq! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign! $\endgroup$ Commented Dec 10, 2014 at 23:02
  • $\begingroup$ I just deleted my answer but the way to do what you ask in the edit is to use @kgulers LegendLayout where I have written "Column". But in that case the index order will be {1, 2, 3, 4} $\endgroup$ Commented Dec 10, 2014 at 23:20
  • $\begingroup$ @MikeHoneychurch Why did you do that? I was going to accept yours (I don't have enough reputation points to do so as a newb) because yours actually allow for custom ordering. Could you be a bit more specific? I want to do something like LegendLayout -> [[{1, 3, 2, 4}]]] rather than LegendLayout -> (Grid@Transpose@Partition[Row /@ #, 2] &) but that doesn't work. $\endgroup$ Commented Dec 10, 2014 at 23:22
  • $\begingroup$ @user174118 Take a look at the edit in my answer $\endgroup$ Commented Dec 10, 2014 at 23:38
  • $\begingroup$ ok I undeleted it and made the revision $\endgroup$ Commented Dec 11, 2014 at 0:19