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$\begingroup$ Thanks Sjoerd. StringSplit can't be used here because repeated substrings can have unique identifiers. StringTake followed by extracting the complementary ranges and sort them before applying Row works: complementaryRanges = Cases[ ReplacePart[(# - {0, 1}) & /@ Partition[ Drop[Flatten[ SortBy[Join[events[[All, 1]], timex[[All, 1]]], #[[1]] &]], 1], 2, 2, 1], {-1, 2} -> StringLength[I2B2[1, text]]], {s_, e_} /; e > s];Row[Last /@ SortBy[Join[events, timex, {#, StringTake[I2B2[file, text], #]} & /@ complementaryRanges], #[[1]] &]] $\endgroup$

alancalvitti
– alancalvitti

2012-07-01 20:00:35 +00:00
Commented Jul 1, 2012 at 20:00

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