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- $\begingroup$ It's a bit like what I did here, yes? :) Still, your solution can benefit greatly from using the Kummer-transformed version of the function. $\endgroup$J. M.'s missing motivation– J. M.'s missing motivation2012-08-04 10:17:10 +00:00Commented Aug 4, 2012 at 10:17
- $\begingroup$ @J.M. oops, I did not remember that! (I did remember seeing this somewhere but not where). I've added a link! About the transformation, I agree, but I try to avoid specializing things unless absolutely necessary and, in this case, it's not; so I left it general. Plus, it's well described in your post. $\endgroup$acl– acl2012-08-04 11:05:10 +00:00Commented Aug 4, 2012 at 11:05
- $\begingroup$ @J.M. as an aside, seeing that transformation reminds me of a few days of pain resulting from having to manipulate a complicated combination of 2F1 functions a few years ago. In the event, it took more computer time to explicitly evaluate the analytical solutions (which I obtained in the form of series) than to do numerical simulations of the system. That taught me a lesson! $\endgroup$acl– acl2012-08-04 11:08:41 +00:00Commented Aug 4, 2012 at 11:08
- 1$\begingroup$ Heh. Still, sometimes analytical manipulations can yield a form that is eminently more suitable for numerics, so it still pays to try out an identity or two... $\endgroup$J. M.'s missing motivation– J. M.'s missing motivation2012-08-04 11:12:20 +00:00Commented Aug 4, 2012 at 11:12
- $\begingroup$ @J.M. yes, that is pretty much the bulk of my working day, some days. $\endgroup$acl– acl2012-08-04 11:13:18 +00:00Commented Aug 4, 2012 at 11:13
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