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Rev

$\begingroup$ at least now it's not throwing an error. Thanks for the reply. However, solution is not right. It must be oscillatory, but mine, using your code, is not. It exponentially diverges. $\endgroup$

dmitry
– dmitry

2015-08-13 23:10:17 +00:00
Commented Aug 13, 2015 at 23:10
2

$\begingroup$ @DmitryGrinko That's what I got, and it seems wrong to me, too. But the change above is only called in the initialization stage, as far as I can tell. It has nothing to do with the actual integration of the system. So I don't think the divergence is because of my code (for example, cs does not even return a value). It might be because you chose a somewhat low WorkingPrecision combined with a small step size. In any case, FWIW, my first guess is that its a numerics issue. $\endgroup$

Michael E2
– Michael E2

2015-08-13 23:28:24 +00:00
Commented Aug 13, 2015 at 23:28

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