I'd like to create a Dataset from an array, where each column's heading becomes the key for all elements in that column. I can accomplish this using nested Table commands, but was wondering if there is a more elegant way that directly leverages the syntax developed for Datasets. E.g., could this instead be accomplished using GroupBy?:
list = {{"date", "time", "volume"}, {a1, a2, a3}, {b1, b2, b3}, {c1, c2, c3}} Table[<|Table[ list[[1, i]] -> list[[n, i]], {i, 1, Length@list[[1]]}]|>, {n, 2, Length@list}] Dataset@% 
AssociationThread[{"date", "time", "volume"} -> {{a1, a2, a2}, {b1, b2, b3}, {c1, c2, c3}}]$\endgroup$Dataset@AssociationThread[{"date", "time", "volume"} -> {{{a1, a2, a2}}, {{b1, b2, b3}}, {{c1, c2, c3}}}]? Sorry, I'm away from Mathematica at the minute :) (Related: mathematica.stackexchange.com/questions/246088/…) $\endgroup$Rest@list, restructuring it from{{a1, a2, a3}, {b1, b2, b3}, {c1, c2, c3}}to{{{a1, a2, a3}}, {{b1, b2, b3}}, {{c1, c2, c3}}}. I could do that, but then I'm back to using Table. I triedPartition, but it only adds an extra set of braces on the outside:Partition[Rest@list, 3]=>{{{a1, a2, a3}, {b1, b2, b3}, {c1, c2, c3}}}$\endgroup$