The correct answer B shows that velocity is constant for Scenario 1. This means that, along the incline, acceleration = 0 and F_net = 0. Then, kinetic friction (Fk) and the parallel component of weight (mg sinθ) must be equal to each other to cancel out.
Fk = mg sinθ
I also learned that Fs ≤ F_applied. So, in this case, Fs ≤ mg sinθ. In other words,
Fs_max = mg sinθ
However, I also learned that kinetic friction is usually less than static friction (Fs). But, here we are getting
Fk = Fs_max = mg sinθ
I don't understand how Fk = Fs_max here. When I searched it up, I found that kinetic and static friction could be equal if their coefficients of friction are equal but that is apparently very rare. Or when the block is just starting to move. Neither of those situations applies here, I think. Did I make any mistakes in the process of getting the equations, or could Fk = Fs here?
