Questions tagged [invariants]
This tag is for questions relating to invariant, a property of a system which remains unchanged under some transformation. In physics, invariance is related to conservation laws.
356 questions
0 votes
0 answers
44 views
Reconciliation of filtering operation in turbulence
I am studying turbulence more specifically properties of filtering operations given by $$ U(x, t) = \int_{\mathbb{R}^n} G(r, x) U(x-r, t) dr $$ with normalization condition $$ \int_{\mathbb{R}^n} G(r, ...
3 votes
2 answers
280 views
What exactly is meant by Invariance of the Lagrangian?
So I've learnt that the Lagrangian is invariant under point transformations as well as under gauge transformations. Essentially meaning that if $$ \frac{d}{dt}\!\left(\frac{\partial L}{\partial \dot{q}...
7 votes
3 answers
2k views
Is it correct for a rotating uniform charged ring to have current?
I encountered this - a rotating uniform charged ring could produce electric current and magnetic field. I myself find it shouldn’t be. The charges are uniformly distributed. Even so, the ring is ...
2 votes
1 answer
406 views
Sum of even powers of spin operators
Let $S_x$, $S_y$, and $S_z$ be the spin operators of a spin-$j$ particle, I noticed using MATLAB that no matter what irreducible representation I choose for $\frak{su}(2)$, I always find that $S_x^{2k}...
0 votes
0 answers
109 views
For Detecting a Massive Boson via Its Decay Products, Do the Invariant Masses of the Particles That Produce It Have To Be Equal to Its Mass?
Maybe a dumb question, but thinking about Drell-Yan, for example, you can detect the Z boson with the invariant mass of its dilepton decay products. However, do the incoming quark/anti-quark pair also ...
1 vote
1 answer
250 views
Isotropic tensor function
I am studying turbulence and I came across the concept of isotropic tensors, that is tensor that are invariant under rotations and translations. After googling for a while the thing I found is that, ...
0 votes
2 answers
210 views
Understanding how to reduce tensor integrals to scalar integrals with the same number of external lines (renormalization)
Currently in my QFT lecture, we are learning about the renormalization. It was said that one-loop integrals in general can be reduced to scalar integrals, which are easier to solve. As an example I ...
1 vote
2 answers
341 views
Similarity of $E^2-B^2$ and $\mathscr{E}^2-p^2$
Regarding the electromagnetic field, a fundamental invariant is $E^2-B^2$. $E$ is the electric field, $B$ the magnetic field. Regarding the four-momentum of a particle, a fundamental invariant is $\...
0 votes
0 answers
155 views
Constructing a Lorentz Scalar from Bilinear Covariants
I'm probably just overthinking this, but here we go: Let $\gamma^\mu$ be the standard Dirac matrices defined by $\{\gamma^\mu,\gamma^\nu\}=2\eta^{\mu\nu}$, where $\eta^{\mu\nu}$ is the Minkowski ...
3 votes
1 answer
259 views
Power as a Lorentz invariant (Jackson)
In the chapter on Radiation by Moving charges by Jackson, it is stated that Larmor's formula $$P = \frac{2}{3} \frac{q^2}{4\pi \epsilon_0}\frac{\dot{v}^2}{c^3}$$can be generalized to a relativistic ...
0 votes
0 answers
49 views
Why action is Lorentz invariant? [duplicate]
I read a book by Professor Liu Chuan. When talking about action principle, the author says: In classical mechamics, the true trajectory of a system is unique. Thus a trajectory obtained by action ...
0 votes
1 answer
369 views
Does relativity=invariance? [closed]
The relativity principle was first stated by Galileo as follows: Shut yourself up with some friend in the main cabin below decks on some large ship, and have with you there some flies, butterflies, ...
2 votes
3 answers
280 views
Explicit FLRW Killing vector fields
Could someone please lists the killing vectors for the FLRW metric with generic $K$ curvature? \begin{equation} ds^2 = -dt^2 + a(t)^2\left( \frac{dr^2}{1 - k r^2} + r^2 d\theta^2 + r^2 \sin\theta d\...
2 votes
1 answer
161 views
Gauge invariant translational symmetry in the toric code
The ground state of the toric code is written as $|\psi_g\rangle=\prod_v\left( \frac{1+A_v}{2} \right)|000...0\rangle$, where $A_v$ is the star operator (product of $\sigma^x$ operators on the edges ...
1 vote
1 answer
187 views
Wigner's little group: 4-momentum transformation of massive particles
When I was learning about the polarizations of massive and massless particles, I was told that for a massless particle its four-momentum is $p^{\mu}=(p,0,0,p)\;$ (in natural units), so the ...