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Jun 8, 2019 at 4:12 comment added user35915 @candied_orange in astropy.units, if you're talking about that, you would get 50 kilogram-meters and if you multiplied that by cm and divided by s**2 you could convert it to J. For my package the idea would be to give users the possibility to input e.g. an energy in any unit (J, eV, erg) and to have astropy convert it to some default energy unit. Then you can internally just use the value (float or numpy array) instead of the Quantity in astropy linguo.
Jun 7, 2019 at 21:35 answer added StackOverthrow timeline score: -2
Jun 7, 2019 at 16:27 comment added candied_orange I'm still trying to get me head around your use case for this. If I have 5 kg and 10 meters does multiplying them in this package give me 50 kilogram-meters? 50J? Or does it just convert from system to system like feet to meters?
Jun 7, 2019 at 15:10 answer added Doc Brown timeline score: 2
Jun 7, 2019 at 10:55 review First posts
Jun 7, 2019 at 14:03
Jun 7, 2019 at 10:50 history asked user35915 CC BY-SA 4.0