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Nov 5, 2024 at 8:13 vote accept pulpicated
Nov 5, 2024 at 1:32 comment added Bergi "The problem is that I need OpenFile.file to always correspond to an entry in Project.projectFiles" - the OpenFile class you have already doesn't guarantee that. How are OpenFile instances constructed? And which entity controls the list of currently open files (that belong to a project)?
Nov 4, 2024 at 19:52 history became hot network question
Nov 4, 2024 at 16:30 answer added JimmyJames timeline score: 4
Nov 4, 2024 at 15:12 comment added JimmyJames Are you using Java's built-in serialization? Please specify what kind of approach you are using.
Nov 4, 2024 at 11:07 answer added Steve timeline score: 3
Nov 4, 2024 at 7:52 comment added Mike Nakis "The problem is that I need OpenFile.file to always correspond to an entry in Project.projectFiles" -- you have failed to explain why this problem happens. Presumably you are implying that sometimes OpenFile.file does not correspond to an entry in Project.projectFiles. Why doesn't it? What kind of serialization are you doing which prevents this from being the case?
Nov 4, 2024 at 7:34 review Close votes
Nov 9, 2024 at 3:08
Nov 4, 2024 at 7:27 comment added freakish So your project is actually a directed graph, while files are its nodes. In this setup I find the following API cleaner and easier to work with: let the FileRef be just an int, and always use Project explicitly when dealing with it. That way FileRef remains a plain data object, and it is also clear that it is meaningless without the project. Which is exactly the case. Then there are no circular dependencies, (de)serialization becomes simple. Usage is only slightly more complicated, but at least it is explicit, which I often prefer. With this setup you don't need separate OpenFile class as well
Nov 4, 2024 at 3:37 answer added candied_orange timeline score: 11
S Nov 4, 2024 at 2:53 review First questions
Nov 4, 2024 at 9:31
S Nov 4, 2024 at 2:53 history asked pulpicated CC BY-SA 4.0