Timeline for answer to Calling shell functions with xargs by Eremite
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
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| Oct 20, 2021 at 16:18 | comment | added | EndlosSchleife | In general, this would break on shell special characters (e.g. |, #) and ignore white space in input. Instead of letting bash treat the input as code, I suggest letting xargs pass them as-is. echo {1..10} | xargs -n 1 -P4 bash -c "$(declare -f testing);"' testing "$@"; echo "$@";' argv0 | |
| Sep 10, 2016 at 10:49 | history | edited | Ciro Santilli OurBigBook.com | CC BY-SA 3.0 | it's never too late |
| Jun 22, 2016 at 11:56 | history | answered | Eremite | CC BY-SA 3.0 |