I have a Play 2.0 app
TestController.scala
def foo(p1: String) = Action {implicit request => Ok(bar(p1)) } private def bar(p1: String) = { //access request parameter here } Is there a way to use implicit to pass request to bar
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1 Answer
Yes, you can:
def foo(p1: String) = Action { implicit request => Ok(bar(p1)) } private def bar(p1: String)(implicit req: RequestHeader) = "content" The code:
Action { implicit request Calls this method on the Action object:
def apply(block: Request[AnyContent] => Result): Action[AnyContent] = { So, what you called "request" matches the paramater named "block". The "implicit" here is optional: it makes the "request" value available as an implicit parameter to other method/function calls.
The implicit in your "bar" function says that it can take the value of "req" from an implicit value, and doesn't necessarily need to be passed in explicitly.
5 Comments
Bob
Thanks Adam, that works. Follow up question, does the implicit need to be passed as a curried parameter?
Adam Rabung
In scala, it the the parameter list, not the parameter, that is implicit. I'm not sure of the motivation for that.
Adam Rabung
scala> implicit val i = 1 i: Int = 1 scala> implicit val s = "hi" s: java.lang.String = hi scala> def concat(implicit x:Int, y:String) = x + y concat: (implicit x: Int, implicit y: String)String scala> concat res0: String = 1hi
Jay Taylor
With play 2.0.3 I kept getting "Cannot find any HTTP Request here" when I did
def foo[A](i: Int)(implicit request: Request[A]): Baz = { ... }. This error was fixed by changing Request[A] to instead use RequestHeader. Thanks Adam Rabung- your info was a big help.
code4j
With play 2.4.6, I need to use Request[AnyContent]