If you want to use it with reverse() you can do this : request.build_absolute_uri(reverse('view_name', args=(obj.pk, )))

If you can't get access to request then you can't use get_current_site(request) as recommended in some solutions here. You can use a combination of the native Sites framework and get_absolute_url instead. Set up at least one Site in the admin, make sure your model has a get_absolute_url() method, then:

>>> from django.contrib.sites.models import Site >>> domain = Site.objects.get_current().domain >>> obj = MyModel.objects.get(id=3) >>> path = obj.get_absolute_url() >>> url = f'https://{domain}{path}' >>> print(url) 'http://example.com/mymodel/objects/3/' 

https://docs.djangoproject.com/en/dev/ref/contrib/sites/#getting-the-current-domain-for-full-urls

You can also use get_current_site as part of the sites app (from django.contrib.sites.models import get_current_site). It takes a request object, and defaults to the site object you have configured with SITE_ID in settings.py if request is None. Read more in documentation for using the sites framework

e.g.

from django.contrib.sites.shortcuts import get_current_site request = None full_url = ''.join(['http://', get_current_site(request).domain, obj.get_absolute_url()]) 

It isn't as compact/neat as request.build_absolute_url(), but it is usable when request objects are unavailable, and you have a default site url.

In your view, just do this:

base_url = "{0}://{1}{2}".format(request.scheme, request.get_host(), request.path) 

If you don't want to hit the database, you could do it with a setting. Then, use a context processor to add it to every template:

# settings.py (Django < 1.9) ... BASE_URL = 'http://example.com' TEMPLATE_CONTEXT_PROCESSORS = ( ... 'myapp.context_processors.extra_context', ) # settings.py (Django >= 1.9) TEMPLATES = [ { 'BACKEND': 'django.template.backends.django.DjangoTemplates', 'DIRS': [], 'APP_DIRS': True, 'OPTIONS': { 'context_processors': [ 'django.template.context_processors.debug', 'django.template.context_processors.request', 'django.contrib.auth.context_processors.auth', 'django.contrib.messages.context_processors.messages', # Additional 'myapp.context_processors.extra_context', ], }, }, ] # myapp/context_processors.py from django.conf import settings def extra_context(request): return {'base_url': settings.BASE_URL} # my_template.html <p>Base url is {{ base_url }}.</p> 

django-fullurl

If you're trying to do this in a Django template, I've released a tiny PyPI package django-fullurl to let you replace url and static template tags with fullurl and fullstatic, like this:

{% load fullurl %} Absolute URL is: {% fullurl "foo:bar" %} Another absolute URL is: {% fullstatic "kitten.jpg" %} 

These badges should hopefully stay up-to-date automatically:

In a view, you can of course use request.build_absolute_uri instead.

This worked for me in my template:

{{ request.scheme }}://{{ request.META.HTTP_HOST }}{% url 'equipos:marca_filter' %} 

I needed the full url to pass it to a js fetch function. I hope this help you.

Yet another way. You could use build_absolute_uri() in your view.py and pass it to the template.

view.py

def index(request): baseurl = request.build_absolute_uri() return render_to_response('your-template.html', { 'baseurl': baseurl }) 

your-template.html

{{ baseurl }} 

Examine Request.META dictionary that comes in. I think it has server name and server port.

Try the following code:

{{ request.scheme }}://{{ request.META.HTTP_HOST }} 

To create a complete link to another page from a template, you can use this:

{{ request.META.HTTP_HOST }}{% url 'views.my_view' my_arg %} 

request.META.HTTP_HOST gives the host name, and url gives the relative name. The template engine then concatenates them into a complete url.

If you're using django REST framework, you can use the reverse function from rest_framework.reverse. This has the same behavior as django.core.urlresolvers.reverse, except that it uses a request parameter to build a full URL.

from rest_framework.reverse import reverse # returns the full url url = reverse('view_name', args=(obj.pk,), request=request) # returns only the relative url url = reverse('view_name', args=(obj.pk,)) 

Edited to mention availability only in REST framework

I know this is an old question. But I think people still run into this a lot.

There are a couple of libraries out there that supplement the default Django functionality. I have tried a few. I like the following library when reverse referencing absolute urls:

https://github.com/fusionbox/django-absoluteuri

Another one I like because you can easily put together a domain, protocol and path is:

https://github.com/RRMoelker/django-full-url

This library allows you to simply write what you want in your template, e.g.:

{{url_parts.domain}} 

If anyone is interested in fetching the absolute reverse url with parameters in a template , the cleanest way is to create your own absolute version of the {% url %} template tag by extending and using existing default code.

Here is my code:

from django import template from django.template.defaulttags import URLNode, url register = template.Library() class AbsURLNode(URLNode): def __init__(self, view_name, args, kwargs, asvar): super().__init__(view_name, args, kwargs, asvar) def render(self, context): url = super().render(context) request = context['request'] return request.build_absolute_uri(url) @register.tag def abs_url(parser, token): urlNode = url(parser, token) return AbsURLNode( urlNode.view_name, urlNode.args, urlNode.kwargs, urlNode.asvar ) 

Usage in templates:

{% load wherever_your_stored_this_tag_file %} {% abs_url 'view_name' parameter %} 

will render(example):

http://example.com/view_name/parameter/ 

instead of

/view_name/parameter/ 

You can either pass request reverse('view-name', request=request) or enclose reverse() with build_absolute_uri request.build_absolute_uri(reverse('view-name'))

I got it:

wsgiref.util.request_uri(request.META) 

Get the full uri with schema, host, port path and query.

Not for absolute url but I was looking just to get host. If you want to get host in your view.py you can do

def my_view(request): host = f"{ request.scheme }://{ request.META.get('HTTP_HOST') }" 

There is also ABSOLUTE_URL_OVERRIDES available as a setting

https://docs.djangoproject.com/en/2.1/ref/settings/#absolute-url-overrides

But that overrides get_absolute_url(), which may not be desirable.

Instead of installing sites framework just for this or doing some of the other stuff mentioned here that relies on request object, I think the better solution is to place this in models.py

Define BASE_URL in settings.py, then import it into models.py and make an abstract class (or add it to one you're already using) that defines get_truly_absolute_url(). It could be as simple as:

def get_truly_absolute_url(self): return BASE_URL + self.get_absolute_url() 

Subclass it and now you can use it everywhere.

As mentioned in other answers, request.build_absolute_uri() is perfect if you have access to request, and sites framework is great as long as different URLs point to different databases.

However, my use case was slightly different. My staging server and the production server access the same database, but get_current_site both returned the first site in the database. To resolve this, you have to use some kind of environment variable. You can either use 1) an environment variable (something like os.environ.get('SITE_URL', 'localhost:8000')) or 2) different SITE_IDs for different servers AND different settings.py.

Hopefully someone will find this useful!

I came across this thread because I was looking to build an absolute URI for a success page. request.build_absolute_uri() gave me a URI for my current view but to get the URI for my success view I used the following....

request.build_absolute_uri(reverse('success_view_name'))

While working on a project I came to know to get the full/absolute URL in Django.

If your URL looks like this in the address bar:

https://stackoverflow.com/questions/2345708 

And if you want to show the above URL to your template.

1. {{ request.path }} #Without GET parameters.
2. {{ request.get_full_path }} #with GET parameters

For the above two codes, this will print in your template will be

questions/2345708 

and another way to get a full URL is:

• {{request.build_absolute_uri}}

this will print in your template will be:

https://stackoverflow.com/questions/2345708 

request.get_host() will give you the domain.

<div class='col-12 col-md-6'> <p class='lead'>Login</p> {% include 'accounts/snippets/form.html' with form=login_form next_url=request.build_absolute_uri %} </div> 

Here for example am saying load the form and tell the form that the next URL is the current URL which this code rendred from

I use this code :

request.build_absolute_uri('/')[:-1] 

response :

https://yourdomain.com 

request.get_host() 

Use this for request object for APIView in django

If request is around, there are good answers. There's also good answers on how to obtain it in the template. Here a simple option for accessing the url in the backend.

in settings.py:

ABSOLUTE_URL_BASE = "http://yourdomain.com" 

in models.py or wherever:

from django.conf import settings from django.urls import reverse url = settings.ABSOLUTE_URL_BASE + reverse("app:name") 

One could also use this set-up to create a templatetag.

class WalletViewSet(mixins.ListModelMixin, GenericViewSet): serializer_class = WalletSerializers pagination_class = CustomPaginationInvestment def get_queryset(self): ###################################################### print(self.request.build_absolute_uri()) ##################################################### wallet, created = Wallet.objects.get_or_create(owner=self.request.user) return Wallet.objects.filter(id=wallet.id) 

You get output like this

http://localhost:8000/v1/wallet HTTP GET /v1/wallet 200 [0.03, 127.0.0.1:41608]