PHP array merge values from one array into another [closed]

Question

Sorry I have read so many posts to make sense of this and have finally confused myself!

I have 2 arrays:

Array 1:

Array ( [0] => Array ( [ID] => SI012348 [Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.188875 [Tier2] => [Tier3] => [Tier4] => [Delivery] => 0 ) [1] => Array ( [ID] => SI012351 [Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.139 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0 ) [2] => Array ( [ID] => SI012387 [Date] => 14/01/2016 [Month] => 1 [Tier1] => 0.201 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0 ) )

Array 2: (Contains all invoices with Delivery charges)

Array ( [SI000005] => 25 [SI000010] => 15 [SI000054] => 20 [SI000069] => 0 [SI000074] => 20 [SI000076] => 16 )

I need to update Array 1 where SI00000x matches and push the value from Array 2 into the [Delivery] value in Array 1.

I am sure this is straightforward but everything I try either takes an age or crashes!

Please help!

Community · Accepted Answer · 2017-05-23 10:32:38Z

3

You could use this (note the ampersand):

foreach ($arr1 as &$rec) { if (isset($arr2[$rec['ID']])) $rec['Delivery'] = $arr2[$rec['ID']]; }

edited May 23, 2017 at 10:32

CommunityBot

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answered Nov 8, 2016 at 21:50

trincot

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1 Comment

Giles Over a year ago

Thanks for the help! Worked a treat.

JOUM · Accepted Answer · 2016-11-08 21:52:14Z

1

Try this (use a reference)

foreach ($array1 as &$a1) { if(isset($array1[$a1['ID']])) $a1['Delivery'] = $array1[$a1['ID']]; }

answered Nov 8, 2016 at 21:52

JOUM

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1 Comment

Jay Blanchard Over a year ago

Why should the OP "try this"? A good answer will always have an explanation of what was done and why it was done in such a manner, not only for the OP but for future visitors to SO.

Jaime · Accepted Answer · 2016-11-08 21:52:40Z

0

foreach ($array1 as &$a1) { if (isset($array2[$a1['ID']])) { $a1['Delivery'] = $array2[$a1['ID']]; } }

edited Nov 8, 2016 at 21:52

answered Nov 8, 2016 at 21:43

Jaime

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1 Comment

Jaime Over a year ago

Updated. The changes will persist outside the loop.

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