Convert multiple whitespaces into one whitespace in array [duplicate]

Question

I have a varying number of elements in an object called foo

Not knowing the number of objects in advance, how can I convert all multiple whitespaces into one whitespace?

so that

var foo = [[day_1: "Hello World "], [day_2:" Hello World"], [day_3: "Hello World "], [day_4: "Hello World"], [day_5:" Hello World "], [day_6: "Hello World"], [day_7: "Hello World"]]

would become:

var output = [[day_1: "Hello World "], [day_2: " Hello World"], [day_3: "Hello World "], [day_4: "Hello World"], [day_5: " Hello World "], [day_6: "Hello World"], [day_7: "Hello World"]]

I have tried this so far but it is does not produce the expected output as it should be in a for each loop format:

foo.replace(/ +(?= )/g,'')

furkle · Accepted Answer · 2017-01-24 02:19:58Z

So if I'm understanding correctly, you want to iterate through the array and replace all runs of whitespace with a single space. This can be done like so:

var output = []; for (var i = 0; i < foo.length; i++) { output.push(foo[i].replace(/ +/g, ' ')); }

Unless I'm missing something, there should be no need for the positive lookahead you've applied in your regex.

You could alternately do this in a functional style, like so:

var output = foo.map(function(part) { return part.replace(/ +/g, ' ') });

I get foo.map is not a function - I edited the question = foo is actually an Object containing a an array

C L K Kissane · Accepted Answer · 2017-01-24 03:01:04Z

You want to iterate through the array and replace all occurences of whitespace with a single space. This can be done like this:

var output = []; for (var i = 0; i < foo.length; i++) { var temp={}; Object.getOwnPropertyNames(foo[i]).forEach(function(val, idx, array) { temp[val]=foo[i][val].replace(/\s+/g, ' '); }); output.push(temp); }

It seems that you tried applying the method to the whole array, and forgot to apply it to each string in the array.

Also FYI:

The \s in the regex replaces all whitespace, not just spaces.

This iterates through each one of each objects' properties and replaces the values of each one.

I have edited the original question - foo is actually an object

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