How to pass a lambda-function-variable with arguments to std::thread? [duplicate]

More answers: C++ Thread taking reference argument failed compile

I'm creating a callable variable to which I'm assigning a lambda-function with arguments:

auto func = [](int &d) -> void { d++; }; 

How can I use this variable as a std::thread-function passing my argument?

I tried the obvious:

int i; auto t1 = std::thread(func, i); t1.join(); 

This fails with the compiler telling me that func has no no type named ‘type’ in [..]_Callable(_Args...)>::type result_type;.

EDIT: It is related to the reference of the argument. It works when I pass a pointer (int *i) or a copy (int i).