error: expected ‘)’ before ‘[’ token error line is - void display(ptr[i]); this is the error which i get after compilation, what does it mean, i have written a simple program in C
- check it as ptr=ptr[i]; void display(ptr); and inform is there same error?Pankaj Kumar– Pankaj Kumar2011-01-25 06:05:07 +00:00Commented Jan 25, 2011 at 6:05
- 1Why did you remove the code ?Mahesh– Mahesh2011-01-25 06:07:49 +00:00Commented Jan 25, 2011 at 6:07
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6 Answers
I can only imagine you are missing a ')' on the line above that line. But more source code would help in identifying the problem.
1 Comment
William
Even having said that the snippet can see looks particularly dodgy.
Two Issues :
void display(ptr[i]);. You shouldn't include return type while calling the function. Return type should be collected and it is up to the caller to collect it. So, changevoid display(ptr[i]);todisplay(ptr[i]);- main should always return something.
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You need to give more context, but it looks like you are making a forward declaration. If so, you need to provide a formal argument type. Right now it looks like you are supplying an "actual" argument.
Also, be sure you have a semicolon finishing the prior line. The lack of which can give some very strange error messages.
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void display(ptr[i]) seems to be a function declaration, but i is no constant and ptr is no type? What is void for?
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Change
void display(ptr[i]); to
display(ptr[i]); When calling a function you don't need to specify the return type.
Also there is a typo in:
for(i-0;i<2;i++) I guess you meant i=0
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EDIT
When calling display, you should just do it like this:
display(ptr[i]); If you insist on clarifying that its type is void, you can use this:
(void)display(ptr[i]); You're also missing this at the top of your file:
#include <stdio.h> You will need that for the scanf function.
