Insert array value on string php [duplicate]

Question

I'm getting an error trying to make this

$array = array("text"); echo "text $array['0']";

it's possible to make it shis way instead concatenate

echo "text ".$array['0'];

Or enclose your array element in { } - echo "text {$array['0']}"; — Karlo Kokkak
– Karlo Kokkak, Commented Apr 24, 2018 at 10:48

Niklesh Raut · Accepted Answer · 2018-04-24 10:47:52Z

2

remove single quotes ' inside double quortes ",

echo "text $array[0]";

Live Demo

answered Apr 24, 2018 at 10:47

Niklesh Raut

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4 Comments

Nigel Ren Over a year ago

Always disliked the way PHP has these inconsistent ways of doing things.

Niklesh Raut Over a year ago

This not inconsistency, how php know that, It is direct php variable or variable is used to mix with string. like these exmaple1 and example2

Nigel Ren Over a year ago

If it's in ", miss out the ', if you miss out the ' when it isn't in " you get a notice (Use of undefined constant) if the index is non-numeric. A few too many if's for me.

Niklesh Raut Over a year ago

you can think about execution and conversion (like interpolation). any language uses the conversion before execution, and php aslo does, it converts ["a"] to [a] but if write [a] it treat as constant and convert with the constant value. so its depends how you write and how it convert before execution. Thanks for comment.

Death-is-the-real-truth · Accepted Answer · 2018-04-24 10:48:42Z

1. You need to remove ' around 0

echo "text $array[0]";

Output:- https://eval.in/993458

2.Or enclose array element with {}

echo "text {$array['0']}";

Output:-https://eval.in/993460

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