Can someone kindly explain why the following throws an exception? And what should I do with variable s to find out whether it contains a number?
s = str(10) if s.isnumeric(): print s When I read Python documentation it seems to me the above should work. See:
https://docs.python.org/3/library/stdtypes.html?highlight=isnumeric#str.isnumeric
But what I get is:
"AttributeError: 'str' object has no attribute 'isnumeric'"
Any help is most appreciated.
Thank you!
replace isnumeric() with isdigit() as
s = str(10) if s.isdigit(): print s 
for python 2 isdigit() and for python 3 isnumeric()
python 2
s = str(10) if s.isdigit(): print s python 3
s = str(10) if s.isnumeric(): print(s) You are obviously using python 2, so a such method does not exist.
That said, the most pythonic way would be to try to convert it
try: print(float(s)) # or int(s) except ValueError: print("s must be numeric") Try using replace with isdigit:
print(s.replace('.', '').isdigit()) 
isdigit(), if that helps. It's not exactly the same, but it's available in Python 2.