Swift iOS version availability - check from * to iOS 13

Question

I have tried to use such check to apply some code that should works only on previous versions of iOS before iOS 13 and it doesn't work correctly i.e. it is executed on iOS 13

if #available(*, iOS 12) { }

I make a workaround like this

if #available(iOS 13, *) { /// Do nothing here } else { }

But i have additional curly braces block

Andre Liberty · Accepted Answer · 2020-11-23 13:17:33Z

4

You can use guard statement

guard #available(iOS 13.0, *) else { // Code for earlier iOS versions return }

edited Nov 23, 2020 at 13:17

answered Sep 24, 2019 at 12:53

Andre Liberty

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Comments

Inshaki · Accepted Answer · 2019-09-24 12:08:21Z

You can get the currentVersion of your OS using:

UIDevice.current.systemVersion

Using this you can easily create your own method.

func SYSTEM_VERSION_LESS_THAN(version: String) -> Bool { return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedAscending }

irmco · Accepted Answer · 2022-05-22 18:30:10Z

In Swift 5.6 (Xcode 13.3+), you can use #unavailable condition.

if #unavailable(iOS 13) { // This code will run on iOS 12.* and earlier }

This is the proposal for reference: SE-0290.

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