3

I've been working on a project that uses structs as storage for strings. I declared a struct consists of char type members:

struct datastore1 { char name[50]; char address[50]; char email[50]; char number[50]; char idnum[50]; };

I'm aware that I can just do char *name, char *address... but let's say we specified it with max length of 50. Then on my function which uses the struct, I malloc'ed it with index size of 30:

struct datastore1 *dsdata = malloc(30 * sizeof(struct datastore1));

Supposedly I finished copying all strings into the struct by accessing each index, How should i free the allocated memory that was used after calling malloc? I tried doing free(dsdata) on the end of the program but I am not sure if it's the right way. Should i free each indexes individually? Please enlighten me. Thank you in advance for the feedback!

Improve this question
2
  • 4
    free(dsdata) is correct. It's actually relatively simple - each malloc should have exactly one free of the same address that the malloc returned. Commented Feb 17, 2020 at 10:10
  • I would suggest struct datastore1 *dsdata = malloc(30 * sizeof(*dsdata)); Commented Feb 17, 2020 at 11:18

4 Answers 4

Reset to default
7

How should i free the allocated memory that was used after calling malloc?

Consider below example,

struct datastore1 *obj1 = malloc(sizeof(struct datastore1)); free(obj1);

Here obj1 is pointing to the block of memory of size same as size of datastore1 in order to free you need to send the address which is allocated by malloc.

enter image description here

likewise,

struct datastore1 *obj2 = malloc(3 * sizeof(struct datastore1)); free(obj2);

obj2 is pointing to a block of contiguous memory of size 3 * sizeof(datastore1) you need to pass the base address to free

enter image description here

Should i free each indexes individually?

NO, Since block of memory is allocated only once and you need to free exactly one time.

Let me extend it further,

struct datastore1 *obj3[3]; for(int i=0;i<3;i++) obj3[i] = malloc(sizeof(struct datastore1)); for(int i=0;i<3;i++) free(obj3[i]);

Here obj3 is array of pointer and each index is pointing to different part of memory and hence need to be freed individually.

enter image description here

Note: For simplicity I haven't considered return value from malloc. Null check has to be done on malloc return value.

Improve this answer
Sign up to request clarification or add additional context in comments.

Comments

1

1.

How should I free the allocated memory that was used after calling malloc?

I tried doing free(dsdata) on the end of the program but I am not sure if it's the right way.

free(dsdata) is fine, since you allocated the whole space by just one call to malloc with:

struct datastore1 *dsdata = malloc(30 * sizeof(struct datastore1));

To cite the standard (C18), 7.22.3.4 - "The malloc function" (emphasize mine):

7.22.3.4 The malloc function

Synopsis

1

 #include <stdlib.h> void* malloc(size_t size);

Description

2 The malloc function allocates space for an object whose size is specified by size and whose value is indeterminate.

Returns

3 The malloc function returns either a null pointer or a pointer to the allocated space.

It is correct to use free(dsdata) because malloc allocated all of the required space at once and returned a pointer to the first structure variable of this array which is assigned to the pointer of dsdata.

The free() function "knows" that dsdata is a reference to the whole allocated space. You do not need to free each of the 30 structures of type struct datastore1 in memory individually.

2.

Should I free each indexes individually?

No, you do not need and even more important you should not do so; this would be Undefined Behavior:

Citation from the current standard (C18), 7.22.3.5/3 - "The free function" (emphasize mine):

Otherwise, if the argument does not match a pointer earlier returned by a memory management function, or if the space has been deallocated by a call to free or realloc, the behavior is undefined.

Improve this answer

Comments

0

As far as I understand you only used malloc to allocate space for an array of datastore1 struct, so it is sufficient to just do free(dsdata).

If in the struct you would have pointers and you would use malloc to allocate each of them, only than you would need to free each of them first.

Improve this answer

1 Comment

... and if one needed to free internal pointers, too, then that would still be different from freeing each array element individually, as the OP supposed might be necessary.
0

Both answers above are correct, but to fully understand how does it work I recommend you to learn how to use valgrind.
To check if program released memory correctly use

valgrind -v --leak-check=full --track-origins=yes ./your-program

This will execute your program on valgrind's virtual processor and give you full feedback about used resources.

Basically operator [] in C programming language in array definition context causes creation of (lets say to simplify) static array - this means that array is included in size of structure (if defined as part of structure) or is stored on the stack (if defined in function or globally).
The malloc function returns address of block of data you can use. Size of this block is at least as big as you requested. When you use free you release this block wich in this case means all data in block pointed by this address will be released.

Improve this answer

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.