FPU exception when converting float into int32_t

I have a seemingly simple goal: I want to convert a float into an integer-type that is exactly 32 bit wide. The code I am posting works on my windows machine, but not on the Linux device I am trying to run the code in the end. I have tried this first:

float a; a = /*some real number, for example 1.08825e+11*/; if (!isfinite(a)){ return -1; } int32_t b; b = static_cast<int32_t> (a); 

Which does not work -the programs just crashes with this information in the command window:

Runtime received SIGFPE (address: 0xb62cd3b7 reason: floating-point invalid operation)

Then I have found a function in another question on stack overflow that safely converts float into int-data types and have tried to adopt the function for my needs. This is my version:

template <class FloatType> int32_t safeFloatToDINT(const FloatType& num) { //check if float fits into int32_t if (std::numeric_limits<int32_t>::digits < std::numeric_limits<FloatType>::digits) { // check if float is smaller than max int32_t if ((num < static_cast<FloatType>(std::numeric_limits<int32_t>::max())) && (num > static_cast<FloatType>(std::numeric_limits<int32_t>::min()))) { return static_cast<int32_t>(num); //safe to cast } else { std::cerr << "Unsafe conversion of value:" << num << std::endl; //NaN is not defined for int32_t return the largest int32_t value return std::numeric_limits<int32_t>::max(); } } else { //It is safe to cast return static_cast<int32_t>(num); } } 

Unfortunately, b = safeFloatToDINT(a); throws the FPU exception, too. I have also just tried writing b = (int32_t)a; but that does not work either. I would like to know how I can take my float variable and safely convert it into an integer type that spans 32 bit. Thank you in advance.