How can a subclass call a method of the superclass with the same method name of the subclass?

Question

#include <iostream> using namespace std; class Person { public: void sing(); }; class Child : public Person { public: void sing(); }; Person::sing() { cout << "Raindrops keep falling on my head..." << endl; } Child::sing() { cout << "London bridge is falling down..." << endl; } int main() { Child suzie; suzie.sing(); // I want to know how I can call the Person's method of sing here! return 0; }

possible duplicate of How to call Base class method through base class pointer pointing to derived class, Call virtual method from base class on object of derived type. — outis
– outis, Commented Apr 22, 2012 at 0:17

James McNellis · Accepted Answer · 2011-06-09 01:44:00Z

15

suzie.Person::sing();

answered Jun 9, 2011 at 1:44

James McNellis

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3 Comments

Ben Voigt Over a year ago

or Person& sue = suzie; sue.sing();.

James McNellis Over a year ago

or static_cast<Person&>(suzie).sing(); or any variation thereof, yes.

Ben Voigt Over a year ago

I wrote that and then removed it. I try to NEVER use a cast where an implicit conversion will work.

Richard Schneider · Accepted Answer · 2011-06-09 01:48:08Z

The child can use Person::sign().

See http://bobobobo.wordpress.com/2009/05/20/equivalent-of-keyword-base-in-c/ for a good explanation.

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