I'm trying to send a URL to an external website as a callback and I'm wondering if there is a way to pass the URL name from urlpatterns and required arguments.
The solution would return the full path of the URL as a string instead of hardcoding it.
The URL in urls.py looks something like this:
app_name = example_app urlpatterns = [ ... '<int:example_id>/, views.my_function, name='some_name' ] And I would like the URL to be something like this, where 1 is an example_id:
https://my_site_domain.com/example/1/ 
