If anyone still needs this, I found this answer . Based on it and on :not pseudo-class, the initial requirement can be accomplished using something like:
div:not(:has(+ .idontwant)) .iwant { ... }
This approach has an advantage over the general sibling combinator: It also matches backwards, meaning something like:
<div> <div class="idontwant" /> <div class="iwant" /> </div>
(so if you have the .idontwant element first -> case which would be ignored by the general sibling combinator)
Explanation:
div:has(+ .idontwant) would match any div that has a direct sibling with the class idontwant div:not(:has(+ .idontwant)) matches any div that doesn't have a direct sibling with class idontwant - All is left to do is search in the div that doesn't have a direct sibling with the class
idontwant for the class we want.
The selector is quite weird and big, but it does the job, and I think there are (specific) cases where it is quite needed.
Edit (from comments): If anyone needs to style an element only if it has a specific sibling (or if it doesn't) you can still use the :has Pseudo-class to accomplish it (check snippet):
const toogleHasClassEl = document.getElementById("toogleHasClass") toogleHasClassEl.onclick = () => toogleHasClassEl.classList.toggle("specificclass")
div:has(.specificclass) .stylethis { background: orange } div:not(:has(.specificclass)) .stylethis { background: yellow } div:has(.stylethis) .specificclass { background: red }
<div> <div class="stylethis">style this</div> <div id="toogleHasClass" class="specificclass">if this has `specificclass` class (click to toggle)</div> </div> <hr/> <div> <div class="stylethis">style this different</div> <div class="thisdoesnthaveclass">if this doesn't have specific class</div> </div> <hr/> <div> <div class="stylethis">style this different (if alone and therefore doesn't have specific sibling)</div> </div>