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I struggle with a multirow, multicolumn table in latex. So far I have this (messy) code:

\begin{tabular}{cccccccccc} \toprule \multirow{2}{*}{\textbf {A}} & \multirow{2}{*}{\textbf {B}} & \multirow{2}{*}{\textbf {C}} & \multicolumn{3}{c}{\textbf {D}} && D1 & D2 & D3 & \multicolumn{3}{c}{\textbf {E}} && E1 & E2 & E3 & \multirow{2}{*}{\textbf {F}}\\ \cmidrule(lr){1-10} a & b & c & d1 & d2 & d3 & e1 & e3 & e3 & f\\ aa & bb & cc & dd1 & dd2 & dd3 & ee1 & ee3 & ee3 & ff \bottomrule \end{tabular}

Ideally the table would look like this:

multicolumn, multirow table

Subheader D1-E3 should not be bold....

Any help is appreciated.

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    welcome to TEXSE, could you make your script compilable? Commented Sep 26, 2019 at 11:08

4 Answers 4

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I tried to clean your code a little bit.

Here is the result:

\documentclass{article} \usepackage{booktabs} \usepackage{multirow} \begin{document} \begin{tabular}{*{10}{c}} \toprule \multirow{2}{*}{\textbf{A}} & \multirow{2}{*}{\textbf{B}} & \multirow{2}{*}{\textbf{C}} & \multicolumn{3}{c}{\textbf{D}} & \multicolumn{3}{c}{\textbf{E}} & \multirow{2}{*}{\textbf{F}}\\ \cmidrule{4-9} &&& D1 & D2 & D3 & E1 & E2 & E3 & \\ \midrule a & b & c & d1 & d2 & d3 & e1 & e3 & e3 & f\\ aa & bb & cc & dd1 & dd2 & dd3 & ee1 & ee3 & ee3 & ff\\ \bottomrule \end{tabular} \end{document}

It renders like this:

enter image description here

However, if you absolutely need the vertical line, I have no idea how to do it on two rows only...

Enjoy!

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  • No, the vertical line isn't a must. Thank your for your code. I got another solution here: stackoverflow.com/questions/58115402/… which introduces a small gap instead of the vertical line, also very nice layout. Anyway, thanks a lot for your prompt answer. Commented Sep 26, 2019 at 11:56
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I more like the following table design:

enter image description here

\documentclass{article} \usepackage{booktabs, makecell, multirow} \renewcommand\theadfont{\bfseries\normalsize} \renewcommand\theadgape{} \begin{document} \begin{tabular}{*{10}{c}} \toprule \multirow{2.5}{*}{\thead{A}} & \multirow{2.5}{*}{\thead{B}} & \multirow{2.5}{*}{\thead{C}} & \multicolumn{3}{c}{\thead{D}} & \multicolumn{3}{c}{\thead{E}} & \multirow{2.5}{*}{\thead{F}} \\ \cmidrule(l){4-6} \cmidrule(l){7-9} & & & D1 & D2 & D3 & E1 & E2 & E3 & \\ \midrule a & b & c & d1 & d2 & d3 & e1 & e3 & e3 & f\\ aa & bb & cc & dd1 & dd2 & dd3 & ee1 & ee3 & ee3 & ff\\ \bottomrule \end{tabular} \end{document}
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  • is the '2.5' first argument of \multirow the reason for which the A, B, C and F are centered regarding the \cmidrule commands, compared to my solution? I used '2' instead and I got a small shift. Commented Oct 4, 2019 at 14:54
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    @AlexandreQuenon, yes. With this is considered spaces around rules (below of \toprule, around \cmisrule` and above of the \midrule) which sum is about 0.5\baselineskip. This is nice new features of recent ˙multirow` package. Commented Oct 4, 2019 at 15:47
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If you really want to add vertical rules compatible with the horizontal rules of booktabs (which is not at all in the spirit of booktabs) you should try {NiceTabular} of nicematrix. That environment creates PGF/Tikz nodes under the cells, rows and columns of the tabular and it's possible to use these nodes to draw whatever rule you want with Tikz.

\documentclass{article} \usepackage{booktabs} \usepackage{nicematrix} \usepackage{tikz} \begin{document} \begin{NiceTabular}{*{10}{c}} \toprule \RowStyle{\bfseries} \Block{2-1}{A} & \Block{2-1}{B} & \Block{2-1}{C} & \Block{1-3}{D} &&& \Block{1-3}{E} &&& \Block{2-1}{F} \\ \cmidrule(l){4-9} & & & D1 & D2 & D3 & E1 & E2 & E3 & \\ \midrule a & b & c & d1 & d2 & d3 & e1 & e3 & e3 & f\\ aa & bb & cc & dd1 & dd2 & dd3 & ee1 & ee3 & ee3 & ff\\ \bottomrule \CodeAfter \tikz \draw (1-|7) -- (3-|7) ; \end{NiceTabular} \end{document}

You need several compilations because nicematrix uses PGF/Tikz nodes.

Output of the above code

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Added the vertical lines to @Alexandre Quenon (EDIT:Sorry got confused) solution

\documentclass{article} \usepackage{booktabs} \usepackage{multirow} \begin{document} \begin{tabular}{cccccccccc} \toprule \multirow{2}{*}{\textbf{A}} & \multirow{2}{*}{\textbf{B}} & \multirow{2}{*}{\textbf{C}} & \multicolumn{3}{c|}{\textbf{D}} & \multicolumn{3}{|c}{\textbf{E}} & \multirow{2}{*}{\textbf{F}}\\ \cmidrule{4-9} &&& D1 & D2 & \multicolumn{1}{c|}{D3} & E1 & E2 & E3 & \\ \midrule a & b & c & d1 & d2 & d3 & e1 & e3 & e3 & f\\ aa & bb & cc & dd1 & dd2 & dd3 & ee1 & ee3 & ee3 & ff\\ \bottomrule \end{tabular} \end{document}

Result

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  • it works but the problem is that you don't have a continuous vertical line, which is quite the opposite of what you usually want. Commented Sep 26, 2019 at 12:04
  • Yeah, it gets closer when you use \hline but then the head looks not so nice. Commented Sep 26, 2019 at 12:07
  • Instead of \cmidrule{4-9} you can consider using \cline{4-9} Commented Jul 26, 2021 at 17:40

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