Revisions to How can I quickly sum all numbers in a file?

Follow POSIX requirement of `-v` and its arg being separate arguments. Some awk implementations even need it.

edited Sep 28, 2015 at 20:33

Another GNU awk one:

awk -vRS='[0v RS='[0-9]+' '{n+=RT};END{print n}'

A perl one:

perl -lne'$n+=$_ for/\d+/g}{print$n'

A POSIX one:

tr -cs 0-9 '[\n*]' | grep . | paste -sd+sd + - | bc

Another GNU awk one:

awk -vRS='[0-9]+' '{n+=RT};END{print n}'

A perl one:

perl -lne'$n+=$_ for/\d+/g}{print$n'

A POSIX one:

tr -cs 0-9 '[\n*]' | grep . | paste -sd+ - | bc

Another GNU awk one:

awk -v RS='[0-9]+' '{n+=RT};END{print n}'

A perl one:

perl -lne'$n+=$_ for/\d+/g}{print$n'

A POSIX one:

tr -cs 0-9 '[\n*]' | grep . | paste -sd + - | bc

added 132 characters in body

edited May 27, 2015 at 21:22

Another GNU awk one:

awk -vRS='[0-9]+' '{n+=RT};END{print n}'

A perl one:

perl -lne'$n+=$_ for/\d+/g}{print$n'

A POSIX one:

tr -cs 0-9 '[\n*]' | grep . | paste -sd+ - | bc

Another GNU awk one:

awk -vRS='[0-9]+' '{n+=RT};END{print n}'

Another GNU awk one:

awk -vRS='[0-9]+' '{n+=RT};END{print n}'

A perl one:

perl -lne'$n+=$_ for/\d+/g}{print$n'

A POSIX one:

tr -cs 0-9 '[\n*]' | grep . | paste -sd+ - | bc

answered May 27, 2015 at 21:14

Another GNU awk one:

awk -vRS='[0-9]+' '{n+=RT};END{print n}'

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