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  • maybe like this: ':x;/PATTERN/{$d;N;s/.*\n//;:z;N;bz};N;bx' to avoid the leading newline Commented Jul 24, 2015 at 0:28
  • Can be rewritten as this sed ':;N;$!b;${s/[^PATTERN]*PATTERN[^\n]*\n//}' Commented Jul 24, 2015 at 13:46
  • @User112638726 - no it can't unless you've got a one char pattern or are 100% certain that none of the chars in your pattern can be matched anywhere else in any other order than the one you look for. But it can be written like: sed -ne'/PATTERN/!d;:n' -e'n;p;bn' - Digital Trauma - the previous little loop won't have any extra/missing char issues, and it doesn't stack like Next either - it repeatedly overwrites the current line w/ the next. Commented Jul 24, 2015 at 14:43
  • @mikeserv Yeah, i only checked with single chars. Yours doesn't work either though, if the patterns not found it deletes everything. Commented Jul 24, 2015 at 14:45
  • @User112638726 - damn. Forgot about that. That is an excellent point. So you gotta kinda burn at bOth ends. sed -ne'/PATTERN/!{H;1h;$!d;x;:p' -ep -e'};n;bn' Commented Jul 24, 2015 at 14:57