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Sep 14, 2023 at 12:42 comment added Michael Tsang It doesn't work: Error spawning command line “dbus-launch --autolaunch=8c77b800842a42468876d979195a5a03 --binary-syntax --close-stderr”: Child process exited with code 1
Oct 13, 2010 at 7:14 vote accept Stefan
Oct 8, 2010 at 15:34 comment added Steven D While it is probably better to just use a loop in a shell script you could always do something like who | awk '/\(:[0-9]+\)/ {gsub("[:|(|)]","");print "DISPLAY=:"$5 " sudo -u " $1 " notify-send \"Message\""}' | bash. Also, you might want to see unix.stackexchange.com/questions/1596/…
Oct 8, 2010 at 11:34 vote accept Stefan
Oct 8, 2010 at 11:34
Oct 8, 2010 at 11:31 vote accept Stefan
Oct 8, 2010 at 11:34
Oct 8, 2010 at 11:08 history edited fschmitt CC BY-SA 2.5
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Oct 8, 2010 at 9:49 history edited fschmitt CC BY-SA 2.5
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Oct 8, 2010 at 9:49 comment added tante The command who tells you who is logged in and on which X display that login is. You just might have to filter it somewhat.
Oct 8, 2010 at 9:42 history answered fschmitt CC BY-SA 2.5