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  • arr=($(cut -d ' ' -f1,2 < $*)) mkdir $(for ((i=0;i<${#arr[@]};i=i+2)); do echo ${arr[$i+1]:0:4}${arr[$i]:0:2}; done) Commented Aug 3, 2016 at 15:40
  • Although this may be a correct answer, but because of its relative complexity, I would like to see an explanation of it. Commented Aug 3, 2016 at 18:09