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  • awk '$3 >= 1998998994944' infile Sice your output doesn't have a disk larger than 300000000000 you won't be able to print anything. The syntax will work in general. $3 > some_value then print. Commented Oct 2, 2017 at 8:19
  • I not want to work with files Commented Oct 2, 2017 at 8:24