Revisions to Remove duplicate $PATH entries with awk command

replace rude/offensive/unnecessary/inaccurate language with a more appropriate and accurate equivalent

edit approved Jul 16, 2019 at 21:48

527
5
11

Here's a sleek one:

printf %s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printf %s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printf %s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwedmessed up.

some credit to:

Here's a sleek one:

printf %s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printf %s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printf %s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

Here's a sleek one:

printf %s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printf %s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printf %s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be messed up.

some credit to:

Rollback to Revision 4

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edited Sep 5, 2016 at 14:01

akostadinov

1.2k
12
21

Here's a sleek one:

echoprintf -n%s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

echoprintf -n%s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`echoPATH=`printf -n%s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

Here's a sleek one:

echo -n "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

echo -n "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`echo -n "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

Here's a sleek one:

printf %s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printf %s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printf %s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

added 6 characters in body

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edited Sep 5, 2016 at 9:19

akostadinov

1.2k
12
21

Here's a sleek one:

printfecho %s-n "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printfecho %s-n "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printfPATH=`echo %s-n "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

Here's a sleek one:

printf %s "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

printf %s "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`printf %s "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

Here's a sleek one:

echo -n "$PATH" | awk -v RS=: -v ORS=: '!arr[$0]++'

Longer (to see how it works):

echo -n "$PATH" | awk -v RS=: -v ORS=: '{ if (!arr[$0]++) { print $0 } }'

Ok, since you're new to linux, here is how to actually set PATH without a trailing ":"

PATH=`echo -n "$PATH" | awk -v RS=: '{ if (!arr[$0]++) {printf("%s%s",!ln++?"":":",$0)}}'`

btw make sure to NOT have directories containing ":" in your PATH, otherwise it is gonna be screwed.

some credit to:

don't break on spaces and backslashes

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edited Sep 3, 2016 at 10:54

Gilles 'SO- stop being evil'

866.1k
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1.8k
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echo -n

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edited Jun 14, 2012 at 10:15

akostadinov

1.2k
12
21

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actual command to achieve the desired result

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edited Jun 14, 2012 at 7:57

akostadinov

1.2k
12
21

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answered Jun 14, 2012 at 7:20

akostadinov

1.2k
12
21

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