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I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

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Rahul
Rahul
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I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.

Tweeted twitter.com/#!/StackUnix/status/231708651100962816
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Ifthikhan
Ifthikhan
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Printing decimal to ascii character, my command does not output as intended

I wanted to output a string of all the ascii characters with the following command

for i in `seq 32 127`; do printf "%c" $i; done

The output of the above command is:

33333334444444444555555555566666666667777777777..............

It's the first (from the left) digit of each number.

Looking through this site I came across the answer to my problem How to print all printable ASCII chars in CLI?, however I still don't understand why my original snippet does not output the ascii characters as intended.