Timeline for Does `declare -a A` create an empty array `A` in Bash?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 6, 2019 at 6:00 | history | tweeted | twitter.com/StackUnix/status/1147384687012274176 | ||
| May 28, 2019 at 18:44 | history | became hot network question | |||
| May 28, 2019 at 12:12 | vote | accept | U. Windl | ||
| May 28, 2019 at 11:14 | history | edited | Jeff Schaller♦ | edited tags | |
| May 28, 2019 at 11:09 | answer | added | Stéphane Chazelas | timeline score: 14 | |
| May 28, 2019 at 10:53 | comment | added | user313992 | Well, you could try declare -a P; Q=(), then declare -p P Q or set | grep -w '^[PQ]' to show bash's idea of your variables. Does this satisfy you or are you looking for something deeper? | |
| May 28, 2019 at 10:42 | history | asked | U. Windl | CC BY-SA 4.0 |