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Nov 10, 2020 at 14:06 vote accept naphelge
Nov 10, 2020 at 10:06 comment added Chris Davies The -n has nothing to do with piping instead of printing. It tells sed only to generate output if there's an explicit print instruction
Nov 10, 2020 at 10:05 answer added Chris Davies timeline score: 0
Nov 10, 2020 at 9:59 comment added Chris Davies So really what you're trying to debug is echo '45.60+0.21 (+0.46%)' | sed -n '/^\([0-9]*\.[0-9]*\)[+-].*$/\1/'
Nov 10, 2020 at 5:46 comment added muru If it's not printing anything, there's nothing to pipe.
Nov 10, 2020 at 5:27 comment added naphelge because the result should pipe instead of print
Nov 10, 2020 at 5:04 comment added muru sed -n? Why -n?
Nov 10, 2020 at 4:35 history asked naphelge CC BY-SA 4.0